How can to make a query with LIKE and get all results with mysqli ?

Web Development

This is my code but it dosn't work:

$param = "%{$_POST['user']}%";
$stmt = $db->prepare("SELECT id,Username FROM users WHERE Username LIKE ?");
$stmt->bind_param("s", $param);
$stmt->execute();
$stmt->bind_result($id,$username);
$stmt->fetch();

This code it doesn't seem to work. I have searched it a lot. Also it may return more than 1 row. So how can I get all the results even if it returns more than 1 row?
 

1
Answers

Nov 21st, 2020 By: Harisha

Replies

Ans: You can obtain the results in two different ways


Way -1:


$param = "%{$_POST['user']}%";

$stmt = $db->prepare("SELECT id,username FROM users WHERE username LIKE ?");

$stmt->bind_param("s", $param);

$stmt->execute();

$stmt->bind_result($id,$username);

while ($stmt->fetch()) {

  echo "Id: {$id}, Username: {$username}";

}

Way -2:


$param = "%{$_POST['user']}%";


$stmt = $db->prepare("SELECT id, username FROM users WHERE username LIKE ?");


$stmt->bind_param("s", $param);


$stmt->execute();


$result = $stmt->get_result();


while ($row = $result->fetch_assoc()) {


    echo "Id: {$row['id']}, Username: {$row['username']}";


}

2 years ago - By anil
 
 

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